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Measure of two quantities along with the...

Measure of two quantities along with the precision of respective measuring intrument is `A=2.5ms^(-1)+-0.5ms^(-1),B=0.10s+-0.01s` The value of AB will be

A

`(0.25+-0.08)m`

B

`(0.25+-0.5)`m

C

`(0.25+-0.05)`m

D

`(0.25+-0.135)`m

Text Solution

Verified by Experts

The correct Answer is:
A
`A=2.5ms^-1+-0.5ms^-1`,`B=0.10s+-0.01s`
`x=AB=(2.5)(0.10)=0.25m`
`(trianglex)/(x)=(triangleA)/(A)+(triangleB)/(B)`
`(0.5)/(2.5)+(0.1)/(0.10)=(0.05+0.025)/(0.25)=(0.075)/(0.25)`
`trianglex=0.075=0.08m`
Rounding off to two significant figures.
`AB=(0.25+-0.08)m`
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