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the sum of two numbers is fixed. Then it...

the sum of two numbers is fixed. Then its multiplication is maximum, when

A

each number is half of the sum

B

each number is `(1)/(3)` and `(2)/(3)` respectively of the sum

C

each number is `(1)/(4)` and `(3)/(4)` respectively of the sum

D

none of these

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To solve the problem of finding the maximum multiplication of two numbers whose sum is fixed, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Variables:** Let the two numbers be \( A \) and \( B \). According to the problem, their sum is fixed. We can denote this fixed sum as \( S \): \[ A + B = S \] 2. **Express One Variable in Terms of the Other:** From the equation above, we can express \( B \) in terms of \( A \): \[ B = S - A \] 3. **Write the Multiplication Function:** We want to maximize the product \( P \) of the two numbers: \[ P = A \times B = A \times (S - A) = AS - A^2 \] 4. **Differentiate the Multiplication Function:** To find the maximum value, we need to differentiate \( P \) with respect to \( A \): \[ \frac{dP}{dA} = S - 2A \] 5. **Set the Derivative to Zero:** To find the critical points, set the derivative equal to zero: \[ S - 2A = 0 \] Solving for \( A \): \[ 2A = S \implies A = \frac{S}{2} \] 6. **Find the Corresponding Value of \( B \):** Now, substitute \( A \) back into the equation for \( B \): \[ B = S - A = S - \frac{S}{2} = \frac{S}{2} \] 7. **Conclusion:** Thus, both numbers \( A \) and \( B \) are equal to \( \frac{S}{2} \). Therefore, the multiplication \( A \times B \) is maximized when both numbers are equal to half of the fixed sum \( S \). ### Final Answer: The multiplication of the two numbers is maximum when each number is half of the sum.

To solve the problem of finding the maximum multiplication of two numbers whose sum is fixed, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Variables:** Let the two numbers be \( A \) and \( B \). According to the problem, their sum is fixed. We can denote this fixed sum as \( S \): \[ A + B = S ...
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