If y=x^2, then int0^(2)ydx will be :...

If `y=x^2`, then `int_0^(2)ydx` will be :

A

`(x^3)/(3)+C`

B

`(8)/(3)`

C

`(2)/(3)`

D

0

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The correct Answer is:

B

`y=x^(2)sinx^(3),int_(0)^(2)ydx=int_(0)^(2)x^(2)dx=[(x^(3))/(3)]=(8)/(3)`

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