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Given that vecA+vecB+vecC=0, out of thre...

Given that `vecA+vecB+vecC=0`, out of three vectors two are equal in magnitude and the magnitude of third vector is `sqrt2` times that of either of two having equal magnitude. Then angle between vectors are given by

A

`30^@`,`60^@`,`90^@`

B

`40^@`,`45^@`,90^@`

C

`45^@`,`60^@`,`90^@`

D

`90^@`,`135^@`,`135^@`

Text Solution

Verified by Experts

The correct Answer is:
D


From polygonlaw, three vectors having summation zero should form a closed polygon (triangle) since the two vectors are having same magnitude and the third vector is `sqrt(2)` times that of either of two having equal magnitude, That is the triangle should be right angled triangle.
Angle between A and B, `alpha90^@`
Angle between B and C, `beta=135^@`
Angle between A and C, `gamma=135^@`.
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