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Given that veca and vecb are two non zer...

Given that `veca and vecb` are two non zero vectors, then the value of `(veca + vecb) xx (veca-vecb)` is,

A

0

B

`A^2-B^2`

C

`vecBxxvecA`

D

`2(vecBxxvecA)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(vecA+vecB)xx(vecA-vecB)=vecAxxvecA-vecAxxvecB+vecBxxvecA-vecBxxvecB`
`=0-vecAxxvecB+vecBxxvecA-0=vecBxxvecA+vecBxxvecA=2(vecBxxvecA)`
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