Home
Class 12
PHYSICS
Two adjacent sides of a parallelogram ar...

Two adjacent sides of a parallelogram are respectively by the two vectors `hat(i)+2hat(j)+3hat(k)` and `3hat(i)-2hat(j)+hat(k)`. What is the area of parallelogram?

A

8

B

`8sqrt3`

C

`3sqrt8`

D

192

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the parallelogram formed by the two vectors, we will follow these steps: ### Step 1: Identify the Vectors The two adjacent sides of the parallelogram are given by the vectors: - Vector A: \(\hat{i} + 2\hat{j} + 3\hat{k}\) - Vector B: \(3\hat{i} - 2\hat{j} + \hat{k}\) ### Step 2: Set Up the Cross Product The area of the parallelogram can be calculated using the magnitude of the cross product of the two vectors. The cross product \( \vec{A} \times \vec{B} \) can be computed using the determinant of a matrix formed by the unit vectors and the components of the vectors. \[ \vec{A} \times \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & 3 \\ 3 & -2 & 1 \end{vmatrix} \] ### Step 3: Calculate the Determinant To calculate the determinant, we can expand it as follows: \[ \vec{A} \times \vec{B} = \hat{i} \begin{vmatrix} 2 & 3 \\ -2 & 1 \end{vmatrix} - \hat{j} \begin{vmatrix} 1 & 3 \\ 3 & 1 \end{vmatrix} + \hat{k} \begin{vmatrix} 1 & 2 \\ 3 & -2 \end{vmatrix} \] Calculating each of these 2x2 determinants: 1. For \(\hat{i}\): \[ \begin{vmatrix} 2 & 3 \\ -2 & 1 \end{vmatrix} = (2)(1) - (3)(-2) = 2 + 6 = 8 \] 2. For \(\hat{j}\): \[ \begin{vmatrix} 1 & 3 \\ 3 & 1 \end{vmatrix} = (1)(1) - (3)(3) = 1 - 9 = -8 \] 3. For \(\hat{k}\): \[ \begin{vmatrix} 1 & 2 \\ 3 & -2 \end{vmatrix} = (1)(-2) - (2)(3) = -2 - 6 = -8 \] Putting it all together: \[ \vec{A} \times \vec{B} = 8\hat{i} + 8\hat{j} - 8\hat{k} \] ### Step 4: Find the Magnitude of the Cross Product Now we will find the magnitude of the vector \(\vec{A} \times \vec{B}\): \[ |\vec{A} \times \vec{B}| = \sqrt{(8)^2 + (8)^2 + (-8)^2} = \sqrt{64 + 64 + 64} = \sqrt{192} = 8\sqrt{3} \] ### Step 5: Conclusion The area of the parallelogram is given by the magnitude of the cross product: \[ \text{Area} = 8\sqrt{3} \text{ square units} \]

To find the area of the parallelogram formed by the two vectors, we will follow these steps: ### Step 1: Identify the Vectors The two adjacent sides of the parallelogram are given by the vectors: - Vector A: \(\hat{i} + 2\hat{j} + 3\hat{k}\) - Vector B: \(3\hat{i} - 2\hat{j} + \hat{k}\) ### Step 2: Set Up the Cross Product ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The sides of a parallelogram represented by vectors p = 5hat(i) - 4hat(j) + 3hat(k) and q = 3hat(i) + 2hat(j) - hat(k) . Then the area of the parallelogram is :

The diagonals of a parallelogram are given by the vectors (3 hat(i) + hat(j) + 2hat(k)) and ( hat(i) - 3hat(j) + 4hat(k)) in m . Find the area of the parallelogram .

Show that the vectors 2hat(i)-hat(j)+hat(k) and hat(i)-3hat(j)-5hat(k) are at right angles.

Find the angle between the vectors hat(i)+3hat(j)+7hat(k) and 7hat(i)-hat(j)+8hat(k) .

Find the area of parallelogram whose adjacent sides are represented by the vectors 3hat(i)+hat(j)-2hat(k) and hat(i)-2hat(j)-hat(k) .

Find the angle between the vectors 2 hat(i) - hat(j) - hat(k) and 3 hat(i) + 4 hat(j) - hat(k) .

Find a unit vector perpendicular to each of the vectors hat(i)+2hat(j)-3hat(k) and hat(i)-2hat(j)+hat(k) .

The adjacent sides of a parallelogram are hat(i) + 2 hat(j) + 3 hat(k) and 2 hat (i) - hat(j) + hat(k) . Find the unit vectors parallel to diagonals.

Vector vec(A)=hat(i)+hat(j)-2hat(k) and vec(B)=3hat(i)+3hat(j)-6hat(k) are :

The adjacent sides of a parallelogram are represented by the vectors vec a= hat i+ hat j- hat k\ a n d\ vec b=-2 hat i+ hat j+2 hat kdot Find unit vectors parallel to the diagonals of the parallelogram.