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The x and y-coordinates of a particle at...

The x and y-coordinates of a particle at any time t are given by `x=7t+4t^(2)` and y = 5t, where x and y are in metre and t seconds. The acceleration of particle at t = 5 is

A

zero

B

8 `(m)/(s^2)`

C

20 `(m)/(s^2)`

D

40 `(m)/(s^2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`a=sqrt(a_x^2+a_y^2)=[((d^2x)/(dt^2))^2+((d^2y)/(dt^2))^2]^((1)/(2))`
here `(d^2y)/(dt^2)=0`. hence `a=(d^2x)/(dt^2)=8(m)/(s^2)`
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