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The position vector of a aprticle is giv...

The position vector of a aprticle is given as `vecr=(t^2-4t+6)hati+(t^2)hatj`. The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

A

1 sec

B

2 sec

C

1.5 sec

D

not possible

Text Solution

Verified by Experts

The correct Answer is:
A
`vec(r)=(t^2-4t+6)hati+t^2hatj`,`vecv=(dvecr)/(dt)=2hati+2hatj`
If velocity vector and acceleration vector are perpedicular
`veca.vecv=0`
`(2hati+2hatj).((2t-4)hati+2thatj)=0`
`8t-8=0`,`t=1` sec
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