Home
Class 12
PHYSICS
The velocity of a particle moving in the...

The velocity of a particle moving in the positive direction of x-axis veries as `v=10sqrtx`. Assuming that at `t=0`, particle was at `x=0`

A

The initial velocity of the particle is zero

B

the initial velocity of the particle is `2.5(m)/(s)`.

C

The accelration of the particle is `2.5(m)/(s^2)`.

D

The acceleration of the particle is `50(m)/(s^2)`.

Text Solution

Verified by Experts

The correct Answer is:
A, D
Given `v=10sqrtx`
Putting `x=0` gives `v=0`, so initial velocity of the particle is zero.
`a=(dv)/(dt)=(10)/(2sqrtx)(dx)/(dt)`
`impliesa=(5)/(sqrtx)v=(5)/(sqrtx)10sqrtx=50(m)/(s^2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The velocity of a particle moving in the positive direction of X-axis varies as v=5sqrt(x) . Assuming that at t = 0, particle was at x = 0. What is the acceleration of the particle ?

The velocity of a particle moving in the positive direction of x -axis varies as v = alpha sqrt(x) where alpha is positive constant. Assuming that at the moment t = 0 , the particle was located at x = 0 , find (i) the time dependance of the velocity and the acceleration of the particle and (ii) the mean velocity of the particle averaged over the time that the particle takes to cover first s meters of the path.

The velocity of a particle moving in the positive direction of the x axis varies as v=alphasqrtx , where alpha is a positive constant. Assuming that at the moment t=0 the particle was located at the point x=0 , find: (a) the time dependence of the velocity and the acceleration of the particle, (b) the mean velocity of the particle averaged over the time that the particle takes to cover the first s metres of the path.

The velocity of a particle moving in the positive direction of the X-axis varies as V = KsqrtS where K is a positive constant. Draw V-t graph.

A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity that varies as v=psqrtx . The displacement of the particle varies with time as (where, p is constant)

Velocity of particle moving along positive x-direction is v = (40-10t)m//s . Here,t is in seconds. At time t=0, tha x coordinate of particle is zero. Find the time when the particle is at a distance of 60 m from origin.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

The velocity of a particle defined by the relation v = 8 -0.02x, where v is expressed in m/s and x in meter. Knowing that x = 0 at t = 0, the acceleration at t=0 is

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.