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A particle experiences a constant accele...

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance `S_1` in the first 10 sec and a distance `S_2` in the next 10 sec, Then

A

`S_1=S_2`

B

`S_1=(S_2)/(3)`

C

`S_1=(S^2)/(2)`

D

`S_1=(S_2)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
As `S=ut+(1)/(2)at^2` `because` `S_1=(1)/(2)a(10)^2=50a`
As `v=u+at`
velocity acquired by particle in 10 sec `v=axx10`
for next 10 sec, `S_2=(10a)xx10+(1)/(2)(a)xx(10)^2`
`S_2=150a`
From (i) and (ii) `S_1=(S_2)/(3)`
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