Home
Class 12
PHYSICS
A body is projected vertically up with a...

A body is projected vertically up with a velocity v and after some time it returns to the point from which it was projected. The average velocity and average speed of the body for the total time of flight are

A

`(vecv)/(2)` and `(v)/(2)`

B

0 and `(v)/(2)`

C

0 and 0

D

`(vecv)/(2)` and 0

Text Solution

Verified by Experts

The correct Answer is:
B

Average velocity `=0` because displacement of the body is zero.
`average speed`=``(t otal dista nce covered)/(time of flight)=(2H_(max))/((2u)/(g))`
`impliesv_(av)=((2u^2)/(2g))/((2u)/(g))impliesv_(av)=(u)/(2)`
Velocity of projection`=v` (given)
`v_(av)=(v)/(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body is projected vertically up with u. Its velocity at half its maximum height is

A particle is projected vertically upward with velocity u from a point A , when it returns to the point of projection .

The ratio of the numerical values of the average velocity and average speed of a body is always

The ratio of the numerical values of the average velocity and average speed of a body is always.

A body is projected vertically upward with an initial velocity u. If acceleration due to gravity is g, find the time for which it remains in air.

A body is projected vertically up with a velocity of 58.8 m/s. After 3 s if the acceleration due to gravity of earth disappears. The distance travelled and the velocity of the body at the end of next 5 sec is

A body is projected vertically upward from the surface of the earth, then the velocity-time graph is:-

A body is projected vertically up with velocity 98 "ms"^(-1) . After 2 s if the acceleration due to gravity of earth disappears, the velocity of the body at the end of next 3 s is

A body is projected vertically upwards wth a velocity u=5m//s . After time t another body is projected vertically upward from the same point with a velocity v=3m//s . If they meet in minimum time duration measured from the projection of first body, then t=k/g sec find k (where g is gravitatio acceleration).

A body is projected up with a velocity 50 "ms"^(-1) after one second if accelaration due to gravity disappears then body