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A body falling from a high Minarret trav...

A body falling from a high Minarret travels 40 m in the last 2 seconds of its fall to ground. Height of Minaret in meter is (take, `g=10 ms^(-2)`)

A

60

B

45

C

80

D

50

Text Solution

Verified by Experts

The correct Answer is:
B
Let height of minaret is H and body take time T to fall from top to bottom.
`H=(1)/(2)gT^2`
In last 2 sec, body travels distance of 40 meter so in `(T-2)` sec distance travelled`=(H-40)`m.
`(H-40)=(1)/(2)g(T-2)^2`
By solving (i) and (ii)`T=3` sec and `H=45`m
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