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A man standing on the roof a house of he...

A man standing on the roof a house of height `h` throws one particle vertically downwards and another particle horizontally with same velocity `u`. Find the ratio of their velocities when they reach the earth's surface.

A

`sqrt(2gh+u^2):u`

B

`1:2`

C

`1:1`

D

`sqrt(2gh+u^2):sqrt(2gh)`

Text Solution

Verified by Experts

The correct Answer is:
C


When particle is thrown in vertical down ward direction with velocity u, then final velocity at the ground level is
`v^2=u^2+2gh`
`v=sqrt(u^22gh)`
Another particle is thrown horizontally with same velocity, then at the surface of earth.
Horizontal component of velocity `v_x=u`
Resultant velocity,`v=sqrt(u^2+2gh)`
For both the particle final velocities when they reach the earth's surface are equal
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