A particle is projected from the horizontal x-z plane, in vertical x-y plane where x-axis is horizontal and positive y-axis vertically upwards. The graph of `y` coordinate of the particle v/s time is as shown . The range of the particle is `sqrt3`. Then the speed of the projected particle is:

Options

A. `sqrt3(m)/(s)`
B. `sqrt((403)/(4))(m)/(s)`
C. `2sqrt5(m)/(s)`
D. `sqrt(28)(m)/(s)`

Answer

D

Explanation

From graph `u_y=(dy)/(dt)=tan60^@`
`u_y=tan60^@=sqrt3(m)/(s)`
Range `R=(2u_xu_y)/(g)` or `sqrt3=(2xxu_xxxsqrt3)/(g)`
or `u_x=5`m.s
`u=sqrt(u_x^2+u_y^2)=sqrt(28)`