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A particle is projected from point A on ...


A particle is projected from point A on plane AB, so that `AB=(2u^2tantheta)/(gsqrt3)` in the figure as shown. If u is the velocity of projection, find angle `theta`.

A

`30^@`

B

`60^@`

C

`90^@`

D

`45^@`

Text Solution

Verified by Experts

The correct Answer is:
A
Time of flight `t=(2u sin (2theta-theta))/(g cos theta)=(2u)/(g)tantheta`
`AB=(2u^(2)tantheta)/(gsqrt(3))=(u)/(sqrt3)t` ..(i)
`u_H=ucos2theta`
`AC=u_H.t=ucos2thetat`
`AB=(AC)/(costheta)=(ucos2thetat)/(costheta)` …(ii)
Compare equations (i) and (ii)
`(cos2theta)/(costheta)=(1)/(sqrt3)` or `theta=30^@`
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