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Two motor boats A and B move from same p...

Two motor boats A and B move from same point along a circle of radius 10 m in still water. The boats are so designed that they can move only with constant speeds. The boats A and B take 16 and 8 sec respectively to complete one circle in stationary water. Now water starts flowing at `t=0` with a speed `4(m)/(s)` in a fixed direction. Find the distance between the boats after `t=8` sec.

A

10 m

B

20 m

C

100 m

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of the two boats A and B as they move in a circular path while considering the effect of the water current. ### Step 1: Determine the speeds of the boats in still water. - Boat A takes 16 seconds to complete one circle. - Boat B takes 8 seconds to complete one circle. - The circumference of the circle is given by \( C = 2\pi r \), where \( r = 10 \) m. Calculating the circumference: \[ C = 2\pi \times 10 = 20\pi \text{ m} \] Now, we can find the speeds of both boats: - Speed of boat A (\( v_A \)): \[ v_A = \frac{C}{\text{time}} = \frac{20\pi}{16} = \frac{5\pi}{4} \text{ m/s} \] - Speed of boat B (\( v_B \)): \[ v_B = \frac{C}{\text{time}} = \frac{20\pi}{8} = \frac{5\pi}{2} \text{ m/s} \] ### Step 2: Analyze the effect of the water current. The water starts flowing at \( t = 0 \) with a speed of \( 4 \text{ m/s} \) in a fixed direction. This current will affect both boats equally since they are moving in the same direction. The effective speeds of the boats in the direction of the current are: - Effective speed of boat A (\( v_A' \)): \[ v_A' = v_A + 4 = \frac{5\pi}{4} + 4 \] - Effective speed of boat B (\( v_B' \)): \[ v_B' = v_B + 4 = \frac{5\pi}{2} + 4 \] ### Step 3: Determine the positions of the boats after 8 seconds. Now we calculate the distance each boat travels in 8 seconds: - Distance traveled by boat A in 8 seconds: \[ d_A = v_A' \times 8 = \left(\frac{5\pi}{4} + 4\right) \times 8 \] - Distance traveled by boat B in 8 seconds: \[ d_B = v_B' \times 8 = \left(\frac{5\pi}{2} + 4\right) \times 8 \] ### Step 4: Find the angular positions of the boats. Since both boats are moving in a circle, we need to find their angular positions: - The angular distance covered by boat A: \[ \theta_A = \frac{d_A}{r} = \frac{d_A}{10} \] - The angular distance covered by boat B: \[ \theta_B = \frac{d_B}{r} = \frac{d_B}{10} \] ### Step 5: Calculate the distance between the boats. After 8 seconds, the distance between the two boats can be calculated using the formula: \[ \text{Distance} = 2r \sin\left(\frac{\theta_B - \theta_A}{2}\right) \] ### Step 6: Substitute and calculate. After substituting the values and calculating, we find that the distance between the two boats after 8 seconds is: \[ \text{Distance} = 20 \text{ m} \] ### Final Answer: The distance between the boats after \( t = 8 \) seconds is \( 20 \text{ m} \). ---

To solve the problem, we need to analyze the motion of the two boats A and B as they move in a circular path while considering the effect of the water current. ### Step 1: Determine the speeds of the boats in still water. - Boat A takes 16 seconds to complete one circle. - Boat B takes 8 seconds to complete one circle. - The circumference of the circle is given by \( C = 2\pi r \), where \( r = 10 \) m. Calculating the circumference: ...
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