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Four particles A,B,C and D are in motion...

Four particles `A,B,C` and `D` are in motion. The velocities of one with respect to other are given as `v_(DC)` is `20m//s` towards noth `v_(BC)` is `20m//s` towards east and `v_(BA)` is `20m//s` towards south. Then `v_(DA)` is

A

`20(m)/(s)` towards north

B

`20(m)/(s)` towards south

C

`20(m)/(s)` towards east

D

`20(m)/(s)` towards west

Text Solution

Verified by Experts

The correct Answer is:
D
Let `hati` and `hatj` be unit vectors in direction of east and north respectively.
`vecV_(DC)=20hatj`,`vecV_(BC)=20hati` and `vecV_(BA)=-20hatj`
`vecV_(DA)=vecV_(DC)+vecV_(CB)+vecV_(BA)=20hatj-20hati=-20hatii`
`vecV_(DA)=-20hati`
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