A particle is moving on a circular path ...

A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is `(anglePOQ=40^@`)

A

`2vcos40^@`

B

`2vsin40^@`

C

`2vsin20^@`

D

`2vcos20^@`

Text Solution

Verified by Experts

The correct Answer is:

C

Change is velocity `=2vsin((theta)/(2))=2vsin20^@`

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