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When a celling fan is switched off, its ...

When a celling fan is switched off, its angular velocity falls to half while it makes `36` rotations. How many more rotations will it make before coming to rest ?

A

18

B

12

C

36

D

48

Text Solution

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The correct Answer is:
To solve the problem step by step, we can follow the reasoning outlined in the video transcript: ### Step 1: Define Initial Conditions Let the initial angular velocity of the ceiling fan be \( \omega \). After making 36 rotations, the angular velocity reduces to half, so the final angular velocity after these rotations is: \[ \omega_f = \frac{\omega}{2} \] ### Step 2: Calculate Angular Displacement for 36 Rotations The angular displacement \( \theta \) for 36 rotations can be calculated as: \[ \theta = 36 \times 2\pi = 72\pi \text{ radians} \] ### Step 3: Use the Equation of Motion We can use the third equation of motion for rotational motion, which is: \[ \omega_f^2 = \omega_i^2 + 2\alpha \theta \] Substituting the known values: \[ \left(\frac{\omega}{2}\right)^2 = \omega^2 + 2\alpha(72\pi) \] This simplifies to: \[ \frac{\omega^2}{4} = \omega^2 + 144\pi\alpha \] ### Step 4: Rearranging the Equation Rearranging gives: \[ \frac{\omega^2}{4} - \omega^2 = 144\pi\alpha \] \[ -\frac{3\omega^2}{4} = 144\pi\alpha \] Thus, we can express the angular acceleration \( \alpha \): \[ \alpha = -\frac{3\omega^2}{576\pi} = -\frac{\omega^2}{192\pi} \] ### Step 5: Calculate Total Angular Displacement Until Rest Now, we need to find the total angular displacement until the fan comes to rest. The initial angular velocity is \( \frac{\omega}{2} \) and the final angular velocity is \( 0 \). Using the same equation of motion: \[ 0 = \left(\frac{\omega}{2}\right)^2 + 2\alpha \theta' \] Where \( \theta' \) is the additional angular displacement until rest. Substituting for \( \alpha \): \[ 0 = \frac{\omega^2}{4} + 2\left(-\frac{\omega^2}{192\pi}\right)\theta' \] This simplifies to: \[ 0 = \frac{\omega^2}{4} - \frac{\omega^2}{96\pi}\theta' \] ### Step 6: Solve for \( \theta' \) Rearranging gives: \[ \frac{\omega^2}{96\pi}\theta' = \frac{\omega^2}{4} \] Dividing both sides by \( \omega^2 \) (assuming \( \omega \neq 0 \)): \[ \frac{\theta'}{96\pi} = \frac{1}{4} \] Thus, \[ \theta' = 24\pi \text{ radians} \] ### Step 7: Convert Angular Displacement to Rotations To find the number of rotations \( n \) corresponding to \( \theta' \): \[ n = \frac{\theta'}{2\pi} = \frac{24\pi}{2\pi} = 12 \] ### Final Answer The ceiling fan will make **12 more rotations** before coming to rest. ---

To solve the problem step by step, we can follow the reasoning outlined in the video transcript: ### Step 1: Define Initial Conditions Let the initial angular velocity of the ceiling fan be \( \omega \). After making 36 rotations, the angular velocity reduces to half, so the final angular velocity after these rotations is: \[ \omega_f = \frac{\omega}{2} \] ...
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