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In the figure, at the free end of the li...


In the figure, at the free end of the light string, a force F is supplied to keep the suspended mass of 18 kg at rest. Then the force exerted by the ceiling on the system (assume that the string segments are vertical and the pulleys are light and smooth) is:(`g=10(m)/(s^2)`)

A

60 N

B

120 N

C

180 N

D

240 N

Text Solution

Verified by Experts

The correct Answer is:
D



FBD of 18 kg block
`18xxgimplies=180N` {as it is at rest}
For the lower pulley:
Clearly: `3T_1=TimpliesT_1=60N`
and for the upper pulley:
`T_2=4T_1=240N`
where `T_2` is the force exerted by the celling on the pulley.
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