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A block of mass 2kg slides down the face...

A block of mass `2kg` slides down the face of a smooth `45^@` wedge of mass `9 kg` as shown in the figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge.

A

`2(m)/(sec^2)`

B

`(11)/(sqrt2)(m)/(s^2)`

C

`1(m)/(s^2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

a is accelration of block w.r.t. wedge
For block:
`N+mAsin45^@=mgcos45^@` ..(i)
for wedge:`Nsin45^@=MA` ..(ii)
From (i) and (ii) `A=1(m)/(s^2)`
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