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In the figure shown , A and B are free o...

In the figure shown , A and B are free of to move. All the surfaces are smooth. `(0 lt theta lt 90^(@))`

A

the accelration of A will be more than `gsintheta`

B

the acceleration of A will beless than `gsintheta`

C

normal force on A due to B will be more than `mgcostheta`

D

normal force on A due to B will be less than `mgcostheta`

Text Solution

Verified by Experts

The correct Answer is:
A, D


`ma_0sintheta+N=mgcostheta`
`impliesmgcostheta`
`impliesN=mgcostheta-ma_0sintheta`
`impliesNltmgcostheta`
Hence, (D) is true.
`ma_0costheta+mgsintheta=ma`
`impliesa=gsintheta+a_0costheta`
Hence, acceleration of A
`=sqrt((a-a_0costheta)^2+(a_0sintheta)^2)gtgsintheta`
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