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An ideal speing, with a pointer attached...


An ideal speing, with a pointer attached to its end, hangs next to a scale. With a 100 N weight attached and in equilibrium, the pointer indicates `40` on the scale as shown. Using a 200 N weight instead results in 60 on the scale. Using an unknown weight `X` instead results in `30` on the scale. Find the value of `X` is

Text Solution

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`40=L+(100)/(K)implies60=L+(200)/(K)`
`K=5` and `L=20`
Now `30=20+(x)/(5)impliesx=50`
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