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A block of mass 2 kg is placed on the fl...

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 2.5 N is applied on the block as shown in Fig. 15.4.4. The force of friction between the block and the floor is `(g = 9.8 m//s^(2))`

A

2.5 N

B

5 N

C

7.84 N

D

10 N

Text Solution

Verified by Experts

The correct Answer is:
A
Applied force `=2.5N`
Limmiting friction `=mumg=0.4xx2xx9.8=7.84N`
For the given condition applied force is smaller than limiting frinction.
Static friction on a body`=`Applied force`=2.5N`
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