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The coefficient of friction between 4 kg...

The coefficient of friction between 4 kg and 5kg blocks is 0.2 and between 5kg block and grond is 0.1 respectively Choose the correct statements.

A

minimum force needed to cause system to move is 17 N

B

Whebn force is 4N static friction at all surfaces is 4 N to keep system at rest

C

Maximum acceleration of 4 kg block is `2(m)/(s^2)`

D

Slipping between 4 kg and 5 kg blocks start when F is 17 N

Text Solution

Verified by Experts

The correct Answer is:
C




So block `Q` is moving due to force while block P due to friction .
Friction direction on both `+Q` blocks as shown
first block `Q` will move and P will move with Q so by FBD taking P and Q as system
`F-9=0impliesF=9N`
When applied force is 4N then FBD
$ kg block is moving due to friction and maximum friction force is 8 N.
So acceleration `=(8)/(4)=2(m)/(s^2)=a_(max)`.
Slipping will start at when Q has `+ve` acceleration equal to maximum acceleration of P, i.e., `2(m)/(s^2)`.
`F-17=5xx2impliesF=27N`.
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