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A small mass of 10 g lies in a hemispher...


A small mass of 10 g lies in a hemispherical bowl of radius 0.5 m at a height of 0.1 m from the bottom of the bowl. The mass will be in equilibrius if the bowl rotates at an

A

`(10)/(sqrt3)(rad)/(s)`

B

`10sqrt3(rad)/(s)`

C

`5(rad)/(s)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C


`Nsintheta=mromega^2`
`Nsintheta=mromega^2`
`tantheta=(romega^2)/(g)`
`omega=sqrt((g tantheta)/(r ))`
`omega=5(rad)/(s)`
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