Home
Class 12
PHYSICS
An engine pumps up 100kg of water throug...

An engine pumps up `100kg` of water through a height of `10m` in `5s`. Given that the efficiency of the engine is `60%`, what is the power of the engine? Take `g=10ms^-2`.

A

3.3 KW

B

0.33 KW

C

0.033 KW

D

33 KW

Text Solution

Verified by Experts

The correct Answer is:
A
Work output of engine `=mgh=100xx10xx10=10^4`J
Efficiency `(eta)`=(out put)/(i nput)` `because` input enrgy `=(output)/(eta)`
`=(10^4)/(60)xx100=(10^5)/(6)J`
`power=(i nput en ergy)/(time)=((10^5)/(6))/(5)=(10^5)/(30)=3.3kW`
Promotional Banner

Similar Questions

Explore conceptually related problems

An engine pumps up 100 kg water through a height of 10 m in 5 s . If efficiency of the engine is 60% . What is the power of the engine? Take g = 10 ms^(2) .

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is 75%

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (Take ,g =10 ms^(-2) ).

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (Take ,g =10 ms^(-2) ).

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (Take ,g =10 ms^(-2) ).

An engine consumes 20 kg of fuel per hour. The calorific value of the fuel is 12 Kcal g^(-1). Calculate the efficiency of the engine if the power of the engine is 42 kW.

An engine pumps 373 kg of water upto height of 16 m in 40 seconds. Rated power of engine if its efficiency is 80% is (1 horse power = 746 W and g =10 m/ s^2 )

The power of pump, which can pump 200 kg of water to a height of 50 m in 10 sec, will be

The power of a pump, which can pump 500 kg of water to height 100 m in 10 s is

A motor pump lifts 6 tonnes of water from a height of 25 m to a height 35m from the ground floor in 20 seconds. The power of the pump (in kW) is [g = 10 ms^(-2)]