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An electric field given vecE= 4.0hati -...

An electric field given `vecE= 4.0hati -3.0(y^(2) + 2.0)j` pierces a Gaussian cube of edge length 2.0 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position z is in meters.) what is the electric flux through the (a) top face, (b) bottom face, (c) left face , (b) bottom facem (c) left face, and (d) back face ? (e) what is the net electric flux through the cube ?

Text Solution

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The correct Answer is:
`72N.m^(2)//C; (b)+24Nm^(2)//C (c)-16N.m^(2)//c (d) zero (e) -48N.m^(2)//C.`
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