Home
Class 12
PHYSICS
In figure , a solid sphere of radius a =...

In figure , a solid sphere of radius a = 2.00cm is concentric with a spherical conductiosn shell of inner raedius b =2.00 a and outer radius c=2.40 a. the sphere has a net unifrom charge `q_(1)=+5.00C`. The shell has a net charge `q_(2) =-q_(1)`. Distance (a) r=0 (b) r= a/2.00 (c) r=a (d) r = 1.50 a (e) r= 2.30a and (f) r= 3.50 a ? what si the net charge on the (g) inner and (h) outer surface of the shell ?

Text Solution

Verified by Experts

The correct Answer is:
(a)zero `(b) 5.6 xx 10^(13) N//C (c)1.1xx10^(14) N//C(d) 5 xx 10 ^(13)N//C` € zero (f) zero (g) -5.00 C (h)zero
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC FLUX AND GAUSS LAW

    CENGAGE PHYSICS ENGLISH|Exercise Subjective type|7 Videos
  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS ENGLISH|Exercise Interger|8 Videos
  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS ENGLISH|Exercise DPP 3.5|15 Videos

Similar Questions

Explore conceptually related problems

A hollow conducting sphere of inner radius r and outer radius 2R is given charge Q as shown in figure, then the

A conducting sphere of radius R and a concentric thick spherical shell of inner radius 2R and outer radius 3R is shown in figure. A charge +10Q is given to the shell and inner sphere is earthed. Then charge on inner sphere is

A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d. The inner shell has total charge +2q and the outer shell has charge +4q . (i) What is the total charge on the (a) inner surface of the small shell, (b) outer surface of the small shell (c) inner surface of the large shell, (d) outer surface of the large shell ? (ii) Calculate the electric field in terms of q and the the distance r from the common centre of two shells for (a) r lt a , (b) a lt r lt b , (c) b lt r lt c , (d) c lt r lt d , (e) r gt d

A solid conducting sphere of radius a has a net positive charge 2Q . A conducting spherical shell of inner radius b and outer radius c is concentric with the solid sphere and has a net charge -Q . The surface charge density on the inner and outer surfaces of the spherical shell will be

A point charge q is placed at a distance of r from the centre O of an uncharged spherical shell of inner radius R and outer radius 2R. The electric potential at the centre of the shell will be

A point charge Q is placed inside a conducting spherical shell of inner radius 3R and outer radius 5R at a distance R from the centre of the shell. The electric potential at the centre of the shell will be

A conducting sphere of radius R, carrying charge Q, lies inside uncharged conducting shell of radius 2R. If they are joined by a metal wire,

A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d ( as shown in Fig . 2.121). The inner shell has a total charge + 2 q , and the outer shell has a total charge + 4 q . Calculate the electric field in terms of q and the distance r from the common center of the two shells for b lt r lt c

A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d ( as shown in Fig . 2.121). The inner shell has a total charge + 2 q , and the outer shell has a total charge + 4 q . Calculate the electric field in terms of q and the distance r from the common center of the two shells for c lt r ltd

A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d. The inner shell has total charge +2q, and the outer shell has charge +4q. (K=(1)/(4piepsilon_(0))) Find the electric in terms of q and the distance r from the common centre of the two shells for r gt d .

CENGAGE PHYSICS ENGLISH-ELECTRIC FLUX AND GAUSS LAW-MCQ s
  1. figure shows, in cross section, two Gaussian spheres and two Gaussian ...

    Text Solution

    |

  2. Figure shows four Gaussion surfaces consisting of identical cylindrica...

    Text Solution

    |

  3. In figure , a solid sphere of radius a = 2.00cm is concentric with a s...

    Text Solution

    |

  4. A uniform charge density of 500 nC//m^(3) is distributed throughout a ...

    Text Solution

    |

  5. the net electric flux through each face of a die (singular of dice) ha...

    Text Solution

    |

  6. A Gaussian surface S encloses two charges q(1)= q and q(2) = -qthe fie...

    Text Solution

    |

  7. The electric field in a region is radially outward with magnitude E=A...

    Text Solution

    |

  8. A charge q is placed at the centre of the open end of a cylindrical ve...

    Text Solution

    |

  9. Electric charge is uniformly distributed along a long straight wire of...

    Text Solution

    |

  10. In a region of space having a spherical symmetic distribution of char...

    Text Solution

    |

  11. In a region of space the electric field in the x-direction and proport...

    Text Solution

    |

  12. Figure shows a closed dotted surface which intersects a conduccting un...

    Text Solution

    |

  13. figure shows a neutral metallic sphere with a point charge +Q placed n...

    Text Solution

    |

  14. A and B are semi - spherical surfaces of radius r(1)and r(2) (r(1) lt ...

    Text Solution

    |

  15. the electric field intensity at all points is space is given by vecE...

    Text Solution

    |

  16. the electric field intensity at all points is space is given by vecE...

    Text Solution

    |

  17. the electric field intensity at all points is space is given by vecE...

    Text Solution

    |

  18. Figure, shown above, shows three situations involving a charged partic...

    Text Solution

    |

  19. There are three concentric thin spheres of radius a,b,c (agtbgtc). The...

    Text Solution

    |

  20. The electric field inside a sphere having charge density related to th...

    Text Solution

    |