Home
Class 12
PHYSICS
The potential of an electric field vec(E...

The potential of an electric field `vec(E) = (y hat(i)+x hat(j))` is

A

`V=-xy+`constant

B

`V=-(x+y)+` constant

C

`V=-(x^(2)+y^(2))+` constant

D

V = constant

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS ENGLISH|Exercise DPP 3.3|20 Videos

  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS ENGLISH|Exercise DPP 3.4|15 Videos

  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS ENGLISH|Exercise DPP 3.1|14 Videos

  • ELECTRIC FLUX AND GAUSS LAW

    CENGAGE PHYSICS ENGLISH|Exercise MCQ s|38 Videos

  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise M.C.Q|2 Videos

Similar Questions

Explore conceptually related problems

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is

Find the potential V of an electrostatic field vec E = a(y hat i + x hat j) , where a is a constant.

A surface element vec(ds) = 5 hat(i) is placed in an electric field vec(E) = 4 hat(i) + 4 hat(j) + 4 hat(k) . What is the electric flux emanting from the surface ?

Electric dipole of moment vec(P)=P hat(i) is kept at a point (x, y) in an electric field vec(E )=4x y^(2)hat(i)+4x^(2)y hat(j) . Find the magnitude of force acting on the dipole.

An electric dipole has a fixed dipole moment vec(p) , which makes angle theta with respect to x-axis. When subjected to an electric field vec(E_(1)) = E hat(i) , it experiences a torque vec(T_(1)) = tau hat(k) . When subjected to another electric field vec(E_(2)) = sqrt(3) E_(1) hat(j) , it experiences torque vec(T_(2)) = -vec(T_(1)) . The angle theta is

The displacement of a charge Q in the electric field vec(E) = e_(1)hat(i) + e_(2)hat(j) + e_(3) hat(k) is vec(r) = a hat(i) + b hat(j) . The work done is

Find the potential difference V_(AB) between A (0,0,0) and B (1 m , 1 m,1 m) in an electric field : (i) vec E = (y hat i + x hat j) Vm^-1 (ii) vec E = (3 x^2 y hat i + x^3 hat j) Vm^-1 .

Find out the electric flux through an area 10 m^(2) lying in XY plane due to a electric field vec(E)=2hat(i)-10 hat(j)+5hat(k) .

Charge Q is given a displacement vec r = a hat i + b hat j in an electric field vec E = E_1 hat i + E_2 hat j . The work done is.