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In the given circuit, initially K(1) is ...

In the given circuit, initially `K_(1)` is closed and `K_(2)` is open. Then `K_(1)` is opened and `K_(2)` is closed. If `q_(1),` and `q_(2)'` are charges on `C_(1) and C_(2) and V_(1)` are the voltages respectively, then

A

Charge on `C_(1)` gets redistributed such that `V_(1)=V_(2)`

B

Charge on `C_(1)` gets redistributed such that `Q_(1) = Q_(2)`

C

charge on `C_(1)` gets redistributed such that `C_(1)V_(1)+C_(2)V_(2)=C_(1)E`

D

Charge on `C_(1)` gets redistributed such that `Q_(1)+Q_(2)=C_(1)E`

Text Solution

Verified by Experts

The correct Answer is:
`(A,C,D)`
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