Home
Class 12
PHYSICS
The internal resistances of two cells sh...

The internal resistances of two cells shown are `0.1Omega` and `0.3 Omega`. If `R = 0.2 Omega`, its potential difference across the cell

A

B will be zero

B

A will be zero

C

A and B will be 2V

D

A will be gt 2V and B will be lt 2V

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS ENGLISH|Exercise Kirchhoff s law and simple circuits|15 Videos
  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS ENGLISH|Exercise Combination of Resistance 2|14 Videos
  • COULOMB LAW AND ELECTRIC FIELD

    CENGAGE PHYSICS ENGLISH|Exercise Single Answer Correct Type|22 Videos
  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS ENGLISH|Exercise Interger|8 Videos

Similar Questions

Explore conceptually related problems

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be

A cell of e.m.f. 2 V and internal resistance 1.2 Omega is connected to an ammeter of resistance 0.8 Omega and two resistors of 4.5 Omega and 9 Omega as shown in Fig. find : the potential difference across the 4.5 Omega resistor.

Two resistance of 400 Omega and 800 Omega are connected in series with 6 volt battery of negligible internal resistance. A voltmeter of resistance 10,000 Omega is used to measure the potential difference across 400 Omega . The error in measurement of potential difference in volts approximatley is

A cell of e.m.f. 2V and internal resistance 1.2. Omega is connected with an ammeter of resistance 0.8 Omega and two resistors of 4.5 Omega and 9 Omega as shown in the diagram below: What is the potential difference across the terminals of the cell?

A cell of e.m.f. 1.8 V and internal resistance 2 Omega is connected in series with an ammeter of resistance 0.7 Omega and a resistor of 4.5 Omega as shown in Fig. What is the potential difference across the terminals of the cell ?

A cell of emf 2 V and internal resistance 1.2Omega is connected with an ammeter of resistance 0.8Omega and two resistors of 4.5Omegaand9Omega as shown in the diagram below: What is the potential difference across the terminals of the cell ?

In the circuit diagram given below, a cell of 9 V and internal resistance of 0.5 (Omega) is connected across a resistor A of 2Omega in series and two resistors of 2Omega and 6Omega in parallel. Find The potential difference across the terminals of the cell.

For the given circuit, If internal resistance of cell is 1.5 Omega , then

A cell which has an emf 1.5 V is connectedin series with an external resistance of 10Omega . If the potential difference across the cell is 1.25 V, then the internal resistance of the cell is ("in" Omega)

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is