Home
Class 12
PHYSICS
For comparing the e.m.f.'s of two cells ...

For comparing the e.m.f.'s of two cells with a potentiometer, a standard cell is used to develop a potential gradient along the wires. Which of the following possibilities would make the experiment unsuccessful gt

A

The e.m.f. of the standard cell is larger than the E e.m.f.s of the two cells

B

The diameter of the wires is the same and uniform throughout

C

The number of wires is ten

D

The e.m.f. of the standard cell is smaller than the e.m.f.s of the two cells

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A potential gradient is created in the wire by a standard cell for the comparision of emf's of two cells in a potentiometer experiment. Which possibility of the following will cause failure of the experiment.

A potentiometer consists of a wire of length 4 m and resistance 10Omega . It is connected to a cell of emf 2V.The potential gradient of the wire is

A potentiometer wire 10 long has a resistance of 40Omega . It is connected in series with a resistances box and a 2 v storage cell. If the potential gradient along the wire is 0.01(V)/(m) the resistance unplugged in the box is

A galvanic cell is composed of two hydrogen electrods, one of which is a standard one. In which of the following solutions should the other electrode be immersed to get maximum e.m.f:

Assertion : The e.m.f. of the drivercell in the potentiometer experiment should be greater than the e.m.f. of the cell to determined. reason ; the fall of potential across the potentiometer wire should not be less than the emf of the cell to be determined.

The figure shows a potentiometer arrangement. D is the driving cell, C is the cell whose emf is to be determined. AB is the potentiometer wire and G is a galvanometer. J is a sliding contact which can touch any point on AB. Which of the following are essen tal condition for obtaining balance?

State the working principle of potentiometer. With the help of the circuit diagram, explain how a potentiometer is used to compare the emf's of two primay cells. Obtain the required expression used for comparing the emfs. Write two possible causes for one sided deflection in a potentiometer experiment.

The balancing length for a cell in a potentiometer experiment is 45 cm. In the balanced condition, the current through the potentiometer wire is 2 A. If the total length of the potentiometer wire is 1 m and its total resistance is 60Omega , the emf of the cell is (in Volts) _________.

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is