In the `5th` overtone of an open organ pipe, these are (N-stands for nodes and A- for antinodes)

Answer

To solve the problem of finding the number of nodes and antinodes in the 5th overtone of an open organ pipe, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Overtone**:
- The 5th overtone corresponds to the 6th harmonic in an open organ pipe. In general, the nth overtone corresponds to the (n+1)th harmonic.

2. **Characteristics of Open Organ Pipe**:
- An open organ pipe has antinodes at both ends and nodes in between. The pattern of nodes (N) and antinodes (A) alternates along the length of the pipe.

3. **Finding Nodes and Antinodes**:
- For the nth harmonic in an open organ pipe, the number of nodes (N) is equal to n, and the number of antinodes (A) is equal to n + 1.
- Therefore, for the 6th harmonic (which is the 5th overtone), we have:
- Number of nodes (N) = 6
- Number of antinodes (A) = 6 + 1 = 7

4. **Conclusion**:
- Thus, in the 5th overtone of an open organ pipe, there are 6 nodes and 7 antinodes.

### Final Answer:
- The answer is: **6 nodes (6N) and 7 antinodes (7A)**.