Home
Class 11
PHYSICS
The x-coordinate of a particle moving o...

The x-coordinate of a particle moving on x-axis is given by `x = 3 sin 100 t + 8 cos^(2) 50 t`, where x is in cm and t is time in seconds. Which of the following is/are correct about this motion

A

the motion of the particle is not S.H.M.

B

the amplitude of the S.H.M. of the particle is 5 units

C

the amplitude of the resultant S.H.M. is `sqrt73` units

D

the maximum displacement of the particle from the origin is 9 units.

Text Solution

Verified by Experts

The correct Answer is:
B, D
Promotional Banner

Topper's Solved these Questions

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Subjective type|3 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Single correct anwer type|14 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct Answer Type|5 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger|11 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger type|3 Videos

Similar Questions

Explore conceptually related problems

The equation of a simple harmonic motion is given by x =6 sin 10 t + 8 cos 10 t , where x is in cm, and t is in seconds. Find the resultant amplitude.

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The displacement of a particle performing simple harmonic motion is given by, x=8 "sin" "omega t + 6 cos omega t, where distance is in cm and time is in second. What is the amplitude of motion?

The motion of a particle executing simple harmonic motion is given by X = 0.01 sin 100 pi (t + 0.05) , where X is in metres andt in second. The time period is second is

The position of a particle moving along x-axis is related to time t as follow: x=2 t^(2)-t^(3) , where x is in meters and t is in seconds. a. What is the maximum positive displacement of the particle along the x axis and at what instant does it attain it? b. Describe the motion of the particle. c. What is the distance covered in the first three seconds? d. What is its displacement in the first four seconds ?

The position x of a particle with respect to time t along x-axis is given by x=9t^(2)−t^(3) where x is in metres and t is in seconds. What will be the position of this pariticle when it achieves maximum speed along the + x direction ?

The motion of a particle moving along x-axis is represented by the equation (dv)/(dt)=6-3v , where v is in m/s and t is in second. If the particle is at rest at t = 0 , then

The position x of a particle moving along x - axis at time (t) is given by the equation t=sqrtx+2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds

The position (in meters) of a particle moving on the x-axis is given by: x=2+9t +3t^(2) -t^(3) , where t is time in seconds . The distance travelled by the particle between t= 1s and t= 4s is m.

The displacement of a particle along the x-axis is given by x = a sin^(2) omega t . The motion of the particle corresponds to