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A winding wire which is used to frame a ...

A winding wire which is used to frame a solenoid can bear a maximum 10 A. current If length of solenoid is 80 cm and its corss sectional raedius is 3 cm , then required length of winding wire is (B =0.2T)

A

`1.2xx10^(2)`m

B

`4.8xx10^(2)m`

C

`2.4 xx10^(3) m`

D

`6xx 10^(3) m`

Text Solution

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The correct Answer is:
To solve the problem step by step, we need to find the required length of the winding wire for the solenoid given the parameters. ### Step 1: Understand the formula for the magnetic field in a solenoid The magnetic field \( B \) inside a solenoid is given by the formula: \[ B = \frac{\mu_0 N I}{L} \] where: - \( B \) = magnetic field (0.2 T) - \( \mu_0 \) = permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)) - \( N \) = number of turns of the solenoid - \( I \) = current (10 A) - \( L \) = length of the solenoid (0.8 m) ### Step 2: Rearrange the formula to find \( N \) We can rearrange the formula to solve for \( N \): \[ N = \frac{B L}{\mu_0 I} \] ### Step 3: Substitute the known values into the equation Substituting the known values into the equation: \[ N = \frac{0.2 \times 0.8}{4\pi \times 10^{-7} \times 10} \] ### Step 4: Calculate \( N \) Calculating the numerator: \[ 0.2 \times 0.8 = 0.16 \] Calculating the denominator: \[ 4\pi \times 10^{-7} \times 10 = 4\pi \times 10^{-6} \] Now substituting these values: \[ N = \frac{0.16}{4\pi \times 10^{-6}} = \frac{0.16}{1.25664 \times 10^{-6}} \approx 127,323.95 \] So, rounding off, we get: \[ N \approx 4 \times 10^4 \] ### Step 5: Calculate the total length of the wire The total length of the wire \( L_w \) used in the solenoid can be calculated using the formula: \[ L_w = 2\pi r N \] where \( r \) is the radius of the solenoid (0.03 m). ### Step 6: Substitute values to find \( L_w \) Substituting the values: \[ L_w = 2\pi \times 0.03 \times 4 \times 10^4 \] ### Step 7: Calculate \( L_w \) Calculating: \[ L_w = 2\pi \times 0.03 \times 4 \times 10^4 \approx 2.4 \times 10^3 \, \text{m} \] ### Final Answer The required length of the winding wire is: \[ L_w \approx 2.4 \times 10^3 \, \text{m} \] ---
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