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In youngs double slit experiment the fri...

In youngs double slit experiment the fringes are formed at a distance of 1m from double slits of sepration 0.12mm .calculate the distance of 4th dark band from the centre of screen ?(wavelength is 12000A).

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To solve the problem of finding the distance of the 4th dark band from the center of the screen in Young's double slit experiment, we will follow these steps: ### Step 1: Understand the Formula for Dark Fringes The distance of the m-th dark fringe from the center of the screen is given by the formula: \[ x_m = \frac{(2m - 1) \lambda D}{2d} \] where: - \( x_m \) is the distance of the m-th dark fringe, - \( m \) is the order of the dark fringe (for the 4th dark band, \( m = 4 \)), - \( \lambda \) is the wavelength of the light, - \( D \) is the distance from the slits to the screen, - \( d \) is the separation between the slits. ### Step 2: Convert Given Values to Consistent Units 1. **Wavelength (\( \lambda \))**: Given as 12000 Å (angstroms). - Convert to centimeters: \[ \lambda = 12000 \, \text{Å} = 12000 \times 10^{-10} \, \text{m} = 12 \times 10^{-5} \, \text{cm} \] 2. **Distance to Screen (\( D \))**: Given as 1 m. - Convert to centimeters: \[ D = 1 \, \text{m} = 100 \, \text{cm} \] 3. **Separation between Slits (\( d \))**: Given as 0.12 mm. - Convert to centimeters: \[ d = 0.12 \, \text{mm} = 0.012 \, \text{cm} \] ### Step 3: Substitute Values into the Formula Now, substitute the values into the formula for the 4th dark fringe (\( m = 4 \)): \[ x_4 = \frac{(2 \times 4 - 1) \lambda D}{2d} \] Substituting the known values: \[ x_4 = \frac{(8 - 1) \times (12 \times 10^{-5}) \times 100}{2 \times 0.012} \] \[ x_4 = \frac{7 \times (12 \times 10^{-5}) \times 100}{2 \times 0.012} \] ### Step 4: Calculate the Distance Now, calculate the numerator and denominator: - **Numerator**: \[ 7 \times (12 \times 10^{-5}) \times 100 = 7 \times 12 \times 10^{-3} = 84 \times 10^{-3} = 0.084 \, \text{cm} \] - **Denominator**: \[ 2 \times 0.012 = 0.024 \, \text{cm} \] Now, divide the numerator by the denominator: \[ x_4 = \frac{0.084}{0.024} = 3.5 \, \text{cm} \] ### Final Answer The distance of the 4th dark band from the center of the screen is: \[ \boxed{3.5 \, \text{cm}} \]
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