Home
Class 12
PHYSICS
A conductor ABOCD moves along its bisect...

A conductor `ABOCD` moves along its bisector with a velocity of `1 m//s` through a perpendicular magnetic field of `1 wb//m^(2)`, as shown in fig. if all the four sides are of `1m` length each, then the induced emf between points `A` and `D` is

A

0

B

`1.41` volt

C

`0.71` volt

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
b
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise comprehensive|5 Videos
  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise single correct|8 Videos
  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise Multiple correct Answer Type|3 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise M.C.Q|2 Videos
  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS ENGLISH|Exercise dpp 3.3|15 Videos

Similar Questions

Explore conceptually related problems

A conductor of length 0.1m is moving with a velocity of 4m/s in a uniform magnetic field of 2T as shown in the figure. Find the emf induced ?

A conductor of length 0.1m is moving with a velocity of 4m/ s in a uniform magnetic field of 2T as shown in the figure. Find the emf induced ?

A conductor of length 5 cm is moved paralllel to itself with a speed of 2m//s , perpendicular to a uniform magnetic field of 10^(-3) Wb//m^(2). the induced emf generated is

A conductor of length 5 cm is moved paralllel to itself with a speed of 2m//s , perpendicular to a uniform magnetic field of 10^(-3) Wb//m^(2). the induced emf generated is

Aconductor of lengfht 0.4 m is moving with a speed of 7 m/s perpendicular to a magnetic field of intensity 0.9 Wb//m^(2) .The induced emf across the coduct is

A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of 0.9 Wb//m^(2) . The induced e.m.f. across the conductor will be

An electron, moving with a velocity of 5xx10^(7)ms^(-1) , enters in a magnetic field of 1 "Wb" m^(-1) at an angle of 30^(@0) . Calculate the force on the electron.

A wire of length 50 cm moves with a velocity of 300 m/min, perpendicular to a magnetic field. If the emf induced in the wire is 2 V, then the magnitude of the field in tesla is

A conducting rod of unit length moves with a velocity of 5m/s in a direction perpendicular to its length and perpendicular to a uniform magnetic field of magnitude 0.4T . Find the emf induced between the ends of the stick.

A conductor of 3 m in length is moving perpendicularly to magnetic field of 10^(-4) tesla with the speed of 10^(2)m//s , then the e.m.f. produced across the ends of conductor will be