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Consider the situation shown in figure. ...

Consider the situation shown in figure. The wire `PQ` has mass m , resistance r and can slide on the smooth , horizontal parallel rails separated by a distance l . The resistance of the rails is negligible . A uniform magnetic field B exists in the rectangular region and a resistance R connects the rails outside the field region .

At t = 0 , the wire PQ is pushed towards right with a speed `v_(0)` . Find
the acceleration of the wire at this instant .

A

`v = v_(0) - (2B^(2)l^(2)x)/(m(R + r))`

B

`v = v_(0) - (B^(2)l^(2)x)/(m(R + r))`

C

`v = v_(0) - (B^(2)l^(2)x)/(2m(R + r))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
b
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