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Light of wavelength 12000A is incident o...

Light of wavelength 12000A is incident on a thin glass plate of refractive index`1` such that angle of refraction into plate is 60° .calculate the thickness of plate which will make it appear dark by reflection?

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To solve the problem, we need to find the thickness of the glass plate that will make it appear dark by reflection when light of a specific wavelength is incident on it. Here’s a step-by-step solution: ### Step 1: Identify the given data - Wavelength of light, \( \lambda = 12000 \, \text{Å} \) - Refractive index of glass, \( \mu = 1 \) - Angle of refraction, \( r = 60^\circ \) ### Step 2: Convert the wavelength into meters Since \( 1 \, \text{Å} = 10^{-10} \, \text{m} \), we convert the wavelength: \[ \lambda = 12000 \, \text{Å} = 12000 \times 10^{-10} \, \text{m} = 12 \times 10^{-7} \, \text{m} \] ### Step 3: Use the formula for dark bands in reflected light The condition for dark bands in the reflected light is given by the formula: \[ 2 \mu t \cos r = n \lambda \] where: - \( t \) is the thickness of the plate, - \( n \) is the order of the dark band (we will take \( n = 1 \) for the first dark band), - \( \lambda \) is the wavelength, - \( \mu \) is the refractive index, - \( r \) is the angle of refraction. ### Step 4: Rearrange the formula to find thickness \( t \) Rearranging the formula to solve for \( t \): \[ t = \frac{n \lambda}{2 \mu \cos r} \] ### Step 5: Substitute the known values into the equation Substituting \( n = 1 \), \( \lambda = 12 \times 10^{-7} \, \text{m} \), \( \mu = 1 \), and \( r = 60^\circ \): \[ t = \frac{1 \times 12 \times 10^{-7}}{2 \times 1 \times \cos 60^\circ} \] ### Step 6: Calculate \( \cos 60^\circ \) We know that: \[ \cos 60^\circ = \frac{1}{2} \] ### Step 7: Substitute \( \cos 60^\circ \) into the equation Substituting \( \cos 60^\circ \) into the equation gives: \[ t = \frac{12 \times 10^{-7}}{2 \times 1 \times \frac{1}{2}} = \frac{12 \times 10^{-7}}{1} = 12 \times 10^{-7} \, \text{m} \] ### Step 8: Final answer Thus, the thickness of the glass plate that will make it appear dark by reflection is: \[ t = 12 \times 10^{-7} \, \text{m} = 1.2 \times 10^{-6} \, \text{m} = 1.2 \, \mu m \]
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