In the circuit diagram shown, R = 10 ome...

In the circuit diagram shown, `R = 10 omega, L = 5 mH, E = 10` V and `i = 1 A`. The current is decreasing at the reate of `10^(3) A//S`. Then `(V_(A) - V_(B))`at this instant is :

`10 V`

`15 V`

`20 V`

`25V`

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