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In the circuit of figure, the battery em...

In the circuit of figure, the battery emf is `epsi` the resitance is `R` and the capacitance is C. The switch S is closed for a long time interval, and zero potential difference is measured across the capacitor

After the switch is opened. the potential difference across the capacitor reaches a maximum value of `DeltaV`. What is the value of the inductance?

A

`(C(DeltaV)^(2))/(2epsi^(2))`

B

`(C(DeltaV)^(2))/(epsi^(2))`

C

`(2C(DeltaV)^(2))/(epsi^(2))`

D

`(C(DeltaV)^(2))/(4epsi^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
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