Two waves passing through a region are represented by
`y = ( 1.0 m) sin [( pi cm^(-1)) x - ( 50 pi s^(-1))t]`
and `y = ( 1.5 cm) sin [( pi //2 cm^(-1)) x - ( 100 pi s^(-1)) t]`.
Find the displacement of the particle at ` x = 4.5 cm` at time ` t = 5.0 ms`.

Explanation

To find the displacement of the particle at \( x = 4.5 \, \text{cm} \) and \( t = 5.0 \, \text{ms} \) due to the two waves, we will follow these steps:

### Step 1: Identify the wave equations
The two waves are given by:
1. \( y_1 = (1.0 \, \text{m}) \sin \left( \pi \, \text{cm}^{-1} \, x - 50 \pi \, \text{s}^{-1} \, t \right) \)
2. \( y_2 = (1.5 \, \text{cm}) \sin \left( \frac{\pi}{2} \, \text{cm}^{-1} \, x - 100 \pi \, \text{s}^{-1} \, t \right) \)

### Step 2: Convert units
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