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A string of length 20 cm and linear mass...

A string of length `20 cm` and linear mass density `0.40 g//cm` is fixed at both ends and is kept under a tension of `16 N` . A wave pulse is produced at `t = 0 ` near an ends as shown in Fig. 7.17 (b) , which travels towards the other end . When will the string have the shape shown in the Fig . ( c).

Text Solution

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Given `mu = 0.40 g//cm = ( 0.40)/(1000) xx 100 = 0.040 kg//m`
Wave speed in the stretched string ,
` v = sqrt ((F)/(mu)) = sqrt((16)/( 0.040)) = 20 m//s`
The string will have the same shape after the pulse travels a distance ` = 20 + 20 = 40 cm`
Thus time period ` t = 0.40//20 = 0.02 s`
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