`0.22 g` of a hydrogen (i.e., a compound conatining carbon and hydrogen only) on complete combustion with oxygen gave `0.9 g` water and `0.44 g` carbon dioxide. Show that these results are in accordance with the law of conservation of mass (atomic mass of `C = 12, H = 1, O = 16)`.

Explanation

To show that the results of the combustion of a hydrocarbon are in accordance with the law of conservation of mass, we will follow these steps:

### Step 1: Identify the mass of the hydrocarbon before combustion
The mass of the hydrocarbon (which contains carbon and hydrogen) before combustion is given as:
\[ \text{Mass of hydrocarbon} = 0.22 \, \text{g} \]

### Step 2: Identify the masses of the products formed
During the complete combustion of the hydrocarbon, the products formed are water (H₂O) and carbon dioxide (CO₂). The masses of the products are:
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