Show that the results given below taken together illustrate a law of chemical action: (a) `0.46 g` og amgnesium produces `0.77 g`. Of magnesium oxide, (b) `0.82 g` of magnesium liberates `760 mL` of hydrogen at `STP` from an acid (weight of `1 mL` of hydrogen at `STP = 0.00009 g)`, and (c ) `1.25 g` results from the union of `1.11 g` of oxygen and hydrogen.

Explanation

To show that the given results illustrate a law of chemical action, we will analyze each part of the question step by step.

### Step 1: Analyze Result (a)
**Given:**
- Mass of magnesium (Mg) = 0.46 g
- Mass of magnesium oxide (MgO) produced = 0.77 g

**Calculation:**
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