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In 4 g atoms of Ag. calculate a. Amoun...

In `4 g` atoms of `Ag.` calculate
a. Amount of `Ag.`
b. Weight of one atom of `Ag`. (atoic weight of `Ag = 108`).

Text Solution

Verified by Experts

a. `4 g "atom" = 4 "mol of" Ag`
`1 "mol of" Ag = 108 g`
`4 "mol of" Ag = 108 xx 4 = 432 g`
b. `1 "mol of" Ag = 6.023 xx 10^(23) "atoms"`
`:. 6.023 xx 10^(23) "atoms" =? 108 g`
`1 "atom" implies (1085)/(6.023 xx 10^(23)) g implies 17.93 xx 10^(-23) g`
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