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From 200 mg of CO(2), 10^(21) molecules ...

From `200 mg` of `CO_(2), 10^(21)` molecules are removed. How many grams and moles of `CO_(2)` are left.

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To solve the problem step by step, we will follow these steps: ### Step 1: Understand the given data - Total weight of CO₂ = 200 mg - Number of molecules removed = \(10^{21}\) ### Step 2: Convert the total weight of CO₂ from milligrams to grams Since the final answer needs to be in grams, we convert milligrams to grams: ...
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