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5 mL of a gaseous hydrocarbon was expose...

`5 mL` of a gaseous hydrocarbon was exposed to `30 mL` of `O_(2)`. The resultant gas, on cooling, is formed to measure `25 mL` of which `10 mL` is absrobed by `NaOH` and the remainder by pyrogallol. Determine the molecular formula of hydrocation. All measurements are made at constant pressure and temperature.

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To determine the molecular formula of the hydrocarbon \( C_xH_y \), we will follow these steps: ### Step 1: Write the reaction equation The hydrocarbon \( C_xH_y \) reacts with oxygen \( O_2 \) to produce carbon dioxide \( CO_2 \) and water \( H_2O \). The balanced reaction can be represented as: \[ C_xH_y + O_2 \rightarrow CO_2 + H_2O \] ...
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