The plastic industry uses large amounts of phthalic anhydride `C_(8)H_(4)O_(3)`, made by the controlled
`C_(10) H_(8) + (9)/(2) O_(2) rarr C_(8) H_(4) O_(3) + 2 CO_(2) + (5)/(2) H_(2) O`
Since some of the naphthalene is oxidised to other products, 80% yield is obtained. What weight of phthalic anhydrid would be produced by the oxidation of `256 g` of `C_(10)H_(8)`.
`[Mw "of" C_(10) H_(8) = 128, Mw "of" C_(8) H_(4) O_(3) = 148]`

Explanation

To solve the problem step by step, we will follow the stoichiometry of the given reaction and account for the yield.

### Step 1: Write down the balanced chemical equation
The balanced chemical equation is:
\[ C_{10}H_{8} + \frac{9}{2} O_{2} \rightarrow C_{8}H_{4}O_{3} + 2 CO_{2} + \frac{5}{2} H_{2}O \]

### Step 2: Identify the molar relationships
From the balanced equation, we see that:
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